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6m^/2m=3m
We move all terms to the left:
6m^/2m-(3m)=0
Domain of the equation: 2m!=0We add all the numbers together, and all the variables
m!=0/2
m!=0
m∈R
-3m+6m^/2m=0
We multiply all the terms by the denominator
-3m*2m+6m^=0
We add all the numbers together, and all the variables
6m-3m*2m=0
Wy multiply elements
-6m^2+6m=0
a = -6; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·(-6)·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*-6}=\frac{-12}{-12} =1 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*-6}=\frac{0}{-12} =0 $
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